Calling Functions Lua

Question

My problem is that I have a function that needs to be called before it is referenced. Another words, the code looks like:

doStuff()

local function doStuff()  end

and whenever I try to run it, it cannot reference the function doStuff(). My question is how can I call this function without moving the function above where it is called? So I don't want:

local function doStuff() end

doStuff()

since it will cause errors in other parts of my program.

possible duplicate of lua - how to call function from above it in code (prior to it being defined)? — tckmn
– tckmn, Commented Jan 10, 2015 at 19:11
Why can't you move the definition to be before the call, can you demonstrate the problem? — ryanpattison
– ryanpattison, Commented Jan 10, 2015 at 20:14
The reason is that this function is dependent upon a function between doStuff() and its definition. — user3496349
– user3496349, Commented Jan 10, 2015 at 20:54

Paul Kulchenko · Accepted Answer · 2015-01-10 20:53:32Z

4

a function that needs to be called before it is referenced

You cannot. You need to solve this problem in a different way. The only situation you may need to do that is if you have two functions that recursively call each other. You can do this way:

local a
local function b()
  a()
end
a = function()
  b()
end
a()

This will go into infinite recursion, but you should get the idea. Another option is to use global variables, but you still won't be able to call a function before it's defined (by any means).

answered Jan 10, 2015 at 20:53

Paul Kulchenko

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