Syntax with where in Haskell

Question

I have the following simple definition.

f :: Int -> Int
f x = bla + blub
  where blub = 1
        bla = 1

The compiler gives me the error test.hs:4:21: parse error on input '=' I know about the indention rules, but all seems to be well indented here.

sh03 · Accepted Answer · 2015-01-19 00:13:27Z

3

There's absolutely nothing wrong with your code.

answered Jan 19, 2015 at 0:13

sh03

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1 Comment

In my editor I inserted indention as tabs (not converted to spaces). If I use spaces instead it works. Thanks!