os.close() kills the python script without an exception

Question

The following script:

import os

def call_close(fd):
    try:
        print fd
        os.close(fd)
    except Exception as e:
        print 'Exception:', e

for fd in range(10):
    call_close(fd)

prints

0
1

Nothing more. No exception. Any guess what is happening?

possible related to this article: stackoverflow.com/questions/24173998/… — Paul Lo
– Paul Lo, Commented Jan 30, 2015 at 15:20

Allan · Accepted Answer · 2015-01-30 15:20:37Z

5

From the documentation (emphasis mine):

File descriptors are small integers corresponding to a file that has been opened by the current process. For example, standard input is usually file descriptor 0, standard output is 1, and standard error is 2.

The script isn't terminating; you're closing standard output, so anything printed after that line can't be displayed.

answered Jan 30, 2015 at 15:20

Allan

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user1907906 · Accepted Answer · 2015-01-30 15:20:59Z

4

os.close:

Close file descriptor fd.

Closing fd = 1 closes STDOUT so you will not see any more output.

answered Jan 30, 2015 at 15:20

user1907906

1 Comment

Jiří Polcar Over a year ago

Great. My real problem was that the logging stop working but the reason was the same.

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