How to sort each individual string in a list of strings?

Using list comprehension and str.join:

>>> l1 = ["bba", "yxx", "abc"]
>>> [''.join(sorted(s)) for s in l1]
['abb', 'xxy', 'abc']

by List compression with sorted method and string join method

>>> l1 = ["bba", "yxx", "abc"]
>>> [''.join(sorted(i)) for i in l1]
['abb', 'xxy', 'abc']
>>> 

by lambda

>>> l1
['bba', 'yxx', 'abc']
>>> map(lambda x:"".join(sorted(x)),l1)
['abb', 'xxy', 'abc']

For Python beginner

1. Iterate every item of list l1 by for loop.
2. Use sorted() method to sort item and return list.
3. Use join() method to create string from the list.
4. Use append() list method to add sored item to new list l2.
5. print l2

e.g.

>>> l1
['bba', 'yxx', 'abc']
>>> l2 = []
>>> for i in l1:
...    a = sorted(i)
...    b = "".join(a)
...    l2.append(b)
... 
>>> l2
['abb', 'xxy', 'abc']

Just use the sorted built-in function.

l1 = ["bba", "yxx", "abc"]
print [''.join(sorted(i)) for i in l1]

Another way of using list comprehensions (if your strings have a fixed length of 3) would be:

print ['{0}{1}{2}'.format(*sorted(i)) for i in l1]