Checking internet connection with Python

Question

I'm working on an application that uses internet so I need to check if there is an internet connection at the load of the application so I use this function:

def is_connected():

    try:
        print "checking internet connection.."
        host = socket.gethostbyname("www.google.com")
        s = socket.create_connection((host, 80), 2)
        s.close()
        print 'internet on.'
        return True

    except Exception,e:
        print e
        print "internet off."
    return False

Sometimes it fails although there is an internet connection, it says 'timed out'. I also tried using urllib2 to send a request to Google but it took time and timed out too. Is there a better way to do it? I'm using Windows 7 and Python 2.6.6.

Does this post answer your question?

sharshofski
– sharshofski

2015-02-26 20:37:38 +00:00
Commented Feb 26, 2015 at 20:37 — sharshofski
– sharshofski, Commented Feb 26, 2015 at 20:37
This post didn't answer my question I saw it already

oridamari
– oridamari

2015-02-26 20:40:49 +00:00
Commented Feb 26, 2015 at 20:40 — oridamari
– oridamari, Commented Feb 26, 2015 at 20:40

Joran Beasley · Accepted Answer · 2015-02-26 20:38:04Z

4

you should do something like

def check_internet():
    for timeout in [1,5,10,15]:
        try:
            print "checking internet connection.."
            socket.setdefaulttimeout(timeout)
            host = socket.gethostbyname("www.google.com")
            s = socket.create_connection((host, 80), 2)
            s.close()
            print 'internet on.'
            return True

        except Exception,e:
            print e
            print "internet off."
    return False

or even better (mostly taken from other answer linked in comments)

def internet_on():
    for timeout in [1,5,10,15]:
        try:
            response=urllib2.urlopen('http://google.com',timeout=timeout)
            return True
        except urllib2.URLError as err: pass
    return False

answered Feb 26, 2015 at 20:38

Joran Beasley

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2 Comments

oridamari Over a year ago

can you explain this line you have added to function I used?

Kebman Over a year ago

Why do you test it four times, each for five milliseconds longer?

Kelvin · Accepted Answer · 2015-02-26 20:44:54Z

1

You can also use another Library to do it. If you're pulling in any content I would highly suggest using Requests.

Joran has a great answer, it definitely works. Another approach is:

def checkNet():
    import requests
    try:
        response = requests.get("http://www.google.com")
        print "response code: " + response.status_code
    except requests.ConnectionError:
        print "Could not connect"

The benefit is you can use the response object and just continue on with your work (response.text etc..)

It's always faster to try it and handle the error if it breaks than do needless checks repeatedly.

answered Feb 26, 2015 at 20:44

Kelvin

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Comments

Luca · Accepted Answer · 2018-08-04 16:02:38Z

0

I would suggest you to use urllib. Is a pre-installed library and you don't need to install extra library. That's my propose:

def isConnected():
    import urllib
    from urllib import request
    try:
        urllib.request.urlopen('http://google.com') # If you want you can add the timeout parameter to filter slower connections. i.e. urllib.request.urlopen('http://google.com', timeout=5)

        return True
    except:
        return False

answered Aug 4, 2018 at 16:02

Luca

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Comments

Kiran S · Accepted Answer · 2022-10-03 08:31:30Z

0

Use this function to check internet availability

    def check_internet():
        os.system('ping -c1 github.com > rs_net 2>&1')
        if "0% packet loss" in open('rs_net').read():
            val = 1
        else:
            val = 0
        os.system('rm rs_net > /dev/null 2>&1')
        return val

    if check_internet() == 1:
        print("Connected to network")

answered Oct 3, 2022 at 8:31

Kiran S

15810 bronze badges

Comments

Aryan Rathore · Accepted Answer · 2024-01-27 16:41:18Z

-1

I think this should work, Do this: Make a Def function and put this in it

try:
    print ("checking internet connection..")
    host = socket.gethostbyname("www.google.com")
    s = socket.create_connection((host, 80), 2)
    s.close()
    print ('internet on.')
    return True

except Exception:
    print ("internet off.")

edited Jan 27, 2024 at 16:41

answered Dec 20, 2020 at 10:50

Aryan Rathore

411 silver badge6 bronze badges

2 Comments

Amit Bravo Over a year ago

if I remove s.close() , would it work like a listener ?

Aryan Rathore Over a year ago

Yeah It should work as a listener.

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