How to get for loop data outside for loop

Question

I want the loop data out side forloop, but i'm getting only one value

<form action="<?=$_SERVER['PHP_SELF']?>" method="post">

               <select name="test[]"  multiple="multiple">
                    <option value="test">test</option>
                    <option value="mytesting">mytesting</option>
                    <option value="testingvalue">testingvalue</option>
                    </select>
                <input type="submit" value="Send" />
                   </form>


<?php
    $test=$_POST['test'];
    for($i=0;$i<count($test);$i++)
    {
    $tyy = $test[$i];
    }


?>

I want to get $tyy out side for loop

I want the loop data out side forloop by i am getting only one value

Why would you need a third variable? You already have all the information available in $_POST and $test. — jeroen
– jeroen, Commented Mar 4, 2015 at 9:34

I'm Geeker · Accepted Answer · 2015-03-04 09:34:15Z

1

Use this

$tyy[] = $test[$i];

or you can concat the values by using this

$tyy = "";
for($i=0;$i<count($test);$i++)
    {
    $tyy .= $test[$i];
    }

print_r($tyy)

answered Mar 4, 2015 at 9:34

I'm Geeker

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7 Comments

deb Over a year ago

and one thing i have a problem for this can you solve We have a multiple select drop down but i am not getting drop like we keep for single drop here the code <select multiple> <option>test</option> <option>test1</option> <option>test1</option> </select> <select> <option>test</option> <option>test1</option> <option>test1</option> </select>

I'm Geeker Over a year ago

w3schools.com/tags/tryit.asp?filename=tryhtml_select_multiple check this link

deb Over a year ago

i want w3schools.com/tags/tryit.asp?filename=tryhtml_select like this for multiple

I'm Geeker Over a year ago

so what was prob in that ?

deb Over a year ago

dropdown is not getting like single select dropdown for multiple

|

Sarath Kumar · Accepted Answer · 2015-03-04 09:36:19Z

1

try this..

    $groupStr = "";
    for($i=0; $i< count($test); $i++)
        {
        $groupStr .= $test[$i];
        }

echo $groupStr;

answered Mar 4, 2015 at 9:36

Sarath Kumar

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Comments

Rajnikant Sharma · Accepted Answer · 2015-03-04 09:37:46Z

0

Use $tyy as an array and fill that array in for loop by using array_push method.

 $tyy = array();

 $test=$_POST['test'];
for($i=0;$i<count($test);$i++)
{
   array_push($tyy, $test[$i]);
}

answered Mar 4, 2015 at 9:37

Rajnikant Sharma

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Comments

Rizier123 · Accepted Answer · 2015-03-04 09:39:23Z

0

This is, because you are reassigning it every iteration. So change the line to this:

$tyy[] = $test[$i];
  //^^ See here, Now you are assign the value to a new array element every iteration

So that you have an array which you can use later

Side Note:

1. You know that you already have an array with this data in $test ? But if you want all data as one string you can use this (without a for loop):

$tyy = implode(", ", $test);

2. $_SERVER["PHP_SELF"] is just a reflection of your URL, so this is open for XSS. You can use this to make it save:

<?= htmlspecialchars($_SERVER["PHP_SELF"], ENT_QUOTES, "utf-8"); ?>

edited Mar 4, 2015 at 9:39

answered Mar 4, 2015 at 9:33

Rizier123

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3 Comments

deb Over a year ago

if i print echo $tty; outside for loop i am getting output array

Rizier123 Over a year ago

@deb output array Do you mean you get array as output or what I guess you get Array to string? Also you know that you already have a array with it: $test is the same as you would have in $tyy

Andrei P. Over a year ago

@deb do print_r($tty);

Alun · Accepted Answer · 2015-03-04 09:41:56Z

0

You have created one single variable, which is being overwritten each time you loop, so there is only one value to get.

If you want to access all the values, you need to save into an array instead of a single variable, or append all the values into one value

either

//create an array of values in $tyy
$tyy = $_POST['test'];
//you can now access $tyy by looping through it.

or

$test = $_POST['test'];
$for($i = 0; $i<count($test); $i++)
{
  //list all the values with commas separating them.
  $tyy .= $test[$i].", ";
}

//view the contents by echoing it.
echo $tyy;

answered Mar 4, 2015 at 9:41

Alun

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Comments

user2745280 · Accepted Answer · 2015-03-04 09:43:24Z

-1

But why are you use loop for post data. Your $_POST['test'] is self array so you can use it without for loop. $array = $_POST['test']; try this.

answered Mar 4, 2015 at 9:43

user2745280

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