Converting character to hex in assembler

Question

So right now I'm working on reading in a single character from the keyboard and displaying its hex value. At the moment I believe I'm getting the correct hex value, but it is not being displayed correctly. For example, 'k' is 6F in hex, but it's displaying as '6;'. I know that the correction must be made in my DIS16 procedure, but I'm not sure when and what to do. If anyone can help, I'd really appreciate it.

DIS16   PROC

    mov cx, 0   


    mov bx, 16


numdiv:     

    mov dx, 0   


    div bx


    push dx


    add cx, 1


    cmp ax, 0   


    jne numdiv      


dispnum:


    pop dx


    add dl, 30h



    mov ah, 02h
    int 21h


    loop    dispnum

RET
DIS16   ENDP

"'k' is 6F in hex". No, 'k' is 6B in hex.

Weather Vane
– Weather Vane

2015-03-06 11:59:30 +00:00
Commented Mar 6, 2015 at 11:59 — Weather Vane
– Weather Vane, Commented Mar 6, 2015 at 11:59

Frank Kotler · Accepted Answer · 2015-03-06 06:37:56Z

2

Since the characters 'A' thru 'F' do not immediately follow '9', you have to adjust for that.



; as you have it
pop dx
add dl, 30h
cmp dl, '9'
jbe skip
add dl, 7 ; bump up to 'A' - 'F'
skip:
; print it... as you were

edited Mar 6, 2015 at 6:37

answered Mar 6, 2015 at 6:29

Frank Kotler

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