Have problem changing a value in an array

Question

I have a multi-dimensional array with 4 entries in each value - (1st name, last name, email, password). I am trying to format the password value so I can insert it into a database. As you can see, my results are not what I need. Why is this the result and what should I do to get my intended result? Thanks

php > $newlines[1][3] = "PASSWORD($newlines[1][3)]";  
php > echo $newlines[1][3];  
PASSWORD(Array[3)]

It looks like the ) and ] are transposed, but I'm still not sure what you are going for here. is "PASSWORD" a function? — Matthew Groves
– Matthew Groves, Commented May 24, 2010 at 19:54

Felix Kling · Accepted Answer · 2010-05-24 20:37:34Z

4

You have a typo:

php > $newlines[1][3] = "PASSWORD($newlines[1][3)]";
                                                ^

But this not the only problem. You are accessing a multi-dimensional array and therefore, you have to put the array access into brackets {}. Otherwise, PHP would only subsitute the variable up to the first index (i.e. $newlines[1]). See also variable parsing.

And as $newlines[1][3] is most likely a string, you should also put quotation marks around it:

php > $newlines[1][3] = "PASSWORD('{$newlines[1][3]}')";

or even better in my opinion:

php > $newlines[1][3] = "PASSWORD('" . $newlines[1][3] . "')";

edited May 24, 2010 at 20:37

answered May 24, 2010 at 19:55

Felix Kling

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3 Comments

aliov Over a year ago

Your third suggestion using concatenation did the trick. All of the others returned Array[3] when I wanted the string that was in the Array. Thank you.

Felix Kling Over a year ago

@aliov: The problem was, that if you don't put {} around the variable, PHP will only parse the variable up to the first index (i.e. $newlines[1]) which is an array and therefore prints Array. You are right, even if you had no typo, you would have got the wrong result. Putting it into brackets should work, but personally I find concatenation much more readable anyway (it is easier to see, what is PHP and what not).

aliov Over a year ago

Thanks for the mini-lesson and the sound advice. Much appreciated.

baloo · Accepted Answer · 2010-05-24 19:54:11Z

2

"PASSWORD($newlines[1][3)]"

Should be

"PASSWORD({$newlines[1][3]})"

answered May 24, 2010 at 19:54

baloo

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Comments

JYelton · Accepted Answer · 2010-05-24 19:54:53Z

1

This appears to be a quotation mark placement problem. You want the result of the function Password() rather than the string "Password(-arguments-)".

Drop the quotations around the right side:

php > $newlines[1][3] = password($newlines[1][3]);

answered May 24, 2010 at 19:54

JYelton

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2 Comments

Felix Kling Over a year ago

PASSWORD() is probably the MySQL function.

JYelton Over a year ago

Ah, then in that case, the other answers should suffice as the transposition of bracket and parenthesis looks suspect.

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