Trying to work with while loop in shell script which is causing infinite loop

Question

# !/bin/sh
i=1
while [ $i -lt 10 ]
do 
  echo $i
  i= 'expr $i + 1'
done

example program to display the numbers from 1 to 9..but it is entering into infinite loop while executing..

Piotr Dajlido · Accepted Answer · 2015-03-23 13:40:38Z

1

Your incrementation is causing the problem. Try this:

# !/bin/sh
i=1
while [ $i -lt 10 ]
do 
  echo $i
  i=$(( i+1 ))
done

answered Mar 23, 2015 at 13:40

Piotr Dajlido

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Comments

sair · Accepted Answer · 2015-03-23 13:56:58Z

0

replace the line

i= 'expr $i + 1'

with

i=`expr $i + 1`

u used (') symbol but it is 'back quote symbol'(above tab button)and dont give space between '=' and '`' click here for code

answered Mar 23, 2015 at 13:56

sair

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