How to add more than 1 number in a loop in Bash script?

Question

So I have this loop:

for ((i=100;i<1001;i++));
do
     echo $i
     sleep 1
done

I want to know how I can add 10 every time the loop repeats instead of adding 1. So I want the loop to look something like this: 110 120 130 140 and keep going until it reaches the limit or stopped! Thanks

Change the i++ to whatever operation you want instead.

Etan Reisner
– Etan Reisner

2015-04-09 01:11:02 +00:00
Commented Apr 9, 2015 at 1:11 — Etan Reisner
– Etan Reisner, Commented Apr 9, 2015 at 1:11

Ainz Titor · Accepted Answer · 2015-04-09 01:15:35Z

1

for ((i=100;i<1001;i+=10));
do
     echo $i
     sleep 1
done

Simply change ++ to += 10

answered Apr 9, 2015 at 1:15

Ainz Titor

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2 Comments

Ainz Titor Over a year ago

;) That's my first answer ever on stackoverflow.

Scott Pearce Over a year ago

I am glad you'll remember me! =)

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