Gulp-uglify combine multiple javascript files into a single javascript file

Question

I'm searching for Gulp task that can take multiple javascript files into a single javascript file and compress to one file, like grunt-contrib-uglify.

This what I tried to do so for to simulate grunt-contrib-uglify:

gulp.task('compressJS', function ()
{
    return gulp.src(SomeJSArrayWithALotOfFiles)
        .pipe(concat('application.js'))
        .pipe(rename({suffix: '.min'}))
        .pipe(uglify())
        .pipe(gulp.dest('../application'))
}

My problem with this solution:
I need manually delete the file (application.js.min) before I run the task, otherwise every task execution the new files concatenate to old compressed file (because this line: .pipe(concat('application.js'))).

Why the unvote? this is a very good question and I did a big search before I asked it — cheziHoyzer
– cheziHoyzer, Commented Apr 16, 2015 at 10:47

xsh.7 · Accepted Answer · 2015-04-16 16:18:26Z

3

In your SomeJSArrayWithALotOfFiles, exclude all files that end with .min.js.

As array, including all .js, but excluding .min.js files:

[ '**/*.js', '!**/*.min.js' ]

Or as single string, including all .js files not ending in .min.js:

'**/*!(.min).js'

edited Apr 16, 2015 at 16:18

xsh.7

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answered Apr 16, 2015 at 10:23

Madara's Ghost

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3 Comments

cheziHoyzer Over a year ago

My problem is not the source, the problem is the destination file, please read the question again!

Madara's Ghost Over a year ago

If you don't include the old .min.js file in your src, it won't be concatinated or included in the other operations. So I fail to see how this doesn't solve your problem.

xsh.7 Over a year ago

@cheziHoyzer your problem is indeed the source glob.

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