I have a variable called number of type Int
var number = value!.integerValue as Int
Now I have to create a NSNumber object using that value.
I am trying to use this constructor
value = NSNumber(int: number)
, but it does not work.
It expect the primitive type int, not Int I guess.
Anyone know how to get around this?
Thanks!
You just do value = number
As you can see in the documentation:
the native swift number types generally bridge directly to NSNumber.
Numbers
Swift automatically bridges certain native number types, such as Int and Float, to NSNumber. This bridging lets you create an NSNumber from one of these types:
SWIFT
let n = 42
let m: NSNumber = n
It also allows you to pass a value of type Int, for example, to an argument expecting an NSNumber. Note that because NSNumber can contain a variety of different types, you cannot pass it to something expecting an Int value.
All of the following types are automatically bridged to NSNumber:
Int
UInt
Float
Double
Bool
Swift 3 update
In Swift 3, this bridging conversion is no longer automatic and you have to cast it explicitly like this:
let n = 42
let m: NSNumber = n as NSNumber
error: repl.swift:3:19: error: cannot convert value of type 'Int' to specified type 'NSNumber'
NSNumber by adding as NSNumber in the assignment. Adding it to my answer.
NSNumber(value:1)The issue is because in ObjC, an int is a 32 bit number, and an integer or NSInteger is a 64 bit number.
var number = value!.integerValue as Int
Number is of type Int which corresponds to the ObjC type NSInteger
You now try to create with this:
value = NSNumber(int: number)
Which takes an Int32 or int type, thus resulting in failure. You have a few options that will work.
One:
value = NSNumber(int: Int32(number))
Two (probably better):
value = NSNumber(integer: number)
Three (probably best):
As @Dima points out, you can just set it directly because swift automatically converts:
value = number
For Swift 3 you must use:
var convertedNumber = NSNumber(value: numberToConvert)
