I am developing with apis however I faced with a problem that I have never met.
curl -F "media=@IMAGE_NAME" 'xxxx url'
How do I convert it into python code with requests?
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1stackoverflow.com/questions/13137817/…Ajay– Ajay2015-05-26 03:35:01 +00:00Commented May 26, 2015 at 3:35
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@Ajay Thanks but this is my ture means of this problem:)Octavian– Octavian2015-05-26 06:40:00 +00:00Commented May 26, 2015 at 6:40
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4 Answers
There's a great example of a POST request in the manual. I think yours specifically would be:
r = requests.post("xxx url", data={"media": "@IMAGE_NAME"})
I solved this problem.
files = { 'media': open(image_name, 'rb') }
Then
requests.post(url, files=files)
see http://www.python-requests.org/en/latest/user/quickstart/#post-a-multipart-encoded-file
Comments
If you have multiple -F parameters you can either use a tuple:
requests.post("https://www.example.com", data=[("foo", "bar"), ("baz", "off")])
or a dict:
requests.post("https://www.example.com", data={"key1": "bar", "baz": "off"})
https://docs.python-requests.org/en/latest/user/quickstart/#more-complicated-post-requests show some examples.
Comments
As per your case :
def command_string_generator(method, token, port, account,container=None, obj=None, headers_in=None, curlhead=None):
url = 'xxxx url'
image = "media=@IMAGE_NAME"
command_string = 'curl -F %s %s ' % (image ,url)
print command_string
return command_string
you can use a function like this as per your needs with -F and change accordingly. Hope this might be helpful.Additional parameters are just for convienience.
2 Comments
Octavian
Thanks for your answering but I want to use the requests :p
janonymous
Hahaaaa. Sure your choice. :)