How to remove duplicate values from a multidimentional array according to a key

Question

Simple question have following code but won't work

//Enter your code here, enjoy!
$correo[] = array('valor'=>'[email protected]','registro'=>'23');
$correo[] = array('valor'=>'[email protected]','registro'=>'24');
$correo[] = array('valor'=>'[email protected]','registro'=>'26');

function arrayUnique($myArray){
    if(!is_array($myArray))
        return $myArray;

    foreach ($myArray as &$myvalue){
        $myvalue=serialize($myvalue);
    }

    $myArray=array_unique($myArray);

    foreach ($myArray as &$myvalue){
        $myvalue=unserialize($myvalue);
    }

    return $myArray;

} 

$arr= arrayUnique($correo);

var_dump($arr);

What I am trying to do is remove those row which has repetitive valor key for example the result of above array should be

Array ( 
    [0] => Array ( 
        [valor] => '[email protected]' 
        [registro] => 24 
        ) 
)

Which registro should be considered?

Sougata Bose
– Sougata Bose

2015-05-26 05:04:42 +00:00
Commented May 26, 2015 at 5:04 — Sougata Bose
– Sougata Bose, Commented May 26, 2015 at 5:04
@b0s3 any one as of now

Vikram Anand Bhushan
– Vikram Anand Bhushan

2015-05-26 05:07:16 +00:00
Commented May 26, 2015 at 5:07 — Vikram Anand Bhushan
– Vikram Anand Bhushan, Commented May 26, 2015 at 5:07
Can't see any duplicate values in registro..

Narendrasingh Sisodia
– Narendrasingh Sisodia

2015-05-26 05:26:45 +00:00
Commented May 26, 2015 at 5:26 — Narendrasingh Sisodia
– Narendrasingh Sisodia, Commented May 26, 2015 at 5:26

user3419778 · Accepted Answer · 2015-05-26 05:52:24Z

1

You can do like this...

$correo[] = array('valor'=>'[email protected]','registro'=>'23');
$correo[] = array('valor'=>'[email protected]','registro'=>'24');
$correo[] = array('valor'=>'[email protected]','registro'=>'26');
function arrayUnique($myArray, $uniqueKeyName)  
{ 
    // Unique Array for return  
    $myReturnArray = array();  
    // Array with the md5 hashes  
    $arrayHashes = array();  
    foreach($myArray as $key => $item) {        
        $hash = md5(serialize($item[$uniqueKeyName]));       
          if (!isset($arrayHashes[$hash])) {  
           $arrayHashes[$hash] = $hash;         
           $myReturnArray[] = $item;
        }  
    }  
    return $myReturnArray;  
} 
$arr= arrayUnique($correo, 'valor');
    echo "<pre>";
    print_r($arr);  
    echo "</pre>";

answered May 26, 2015 at 5:52

user3419778

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Comments

Akshay Hegde · Accepted Answer · 2015-05-26 06:09:58Z

You may try like this, since you said any one of registro should be considered.

 [akshay@localhost tmp]$ cat test.php
 <?php

 $array = array(
                 array('valor'=>'[email protected]','registro'=>'23'),
                 array('valor'=>'[email protected]','registro'=>'24'),
                 array('valor'=>'[email protected]','registro'=>'26')
               );

 function remove_dup($array, $key)
 {
    foreach( $array as $v )
    {
        if(! isset($out[ $v[$key] ]  ) )
            $out[$v[$key]] = $v;
    }
    return array_values($out);
 }


 // Input
 print_r( $array );

 // Output
 print_r( remove_dup($array,'valor') );

 ?>

Output

 [akshay@localhost tmp]$ php test.php
 Array
 (
     [0] => Array
         (
             [valor] => [email protected]
             [registro] => 23
         )

     [1] => Array
         (
             [valor] => [email protected]
             [registro] => 24
         )

     [2] => Array
         (
             [valor] => [email protected]
             [registro] => 26
         )

 )

 Array
 (
     [0] => Array
         (
             [valor] => [email protected]
             [registro] => 23
         )

 )

Sougata Bose · Accepted Answer · 2015-05-26 05:10:02Z

0

You can define the function like -

function arrayUnique($myArray){
    if(!is_array($myArray))
        return $myArray;
    $temp = array();
    foreach ($myArray as $myvalue){
        $temp[$myvalue['valor']] = $myvalue;
    }
    return $temp;
}

Store the array with valor as key. It will store only the last one.

answered May 26, 2015 at 5:10

Sougata Bose

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