remove localstorage array object base on value

Question

Says I have this saved key in my localstorage, how to remove the player_id that has value of 2 and shoe size_of 1?

[{"player_id":1,"shoe_size":3},{"player_id":2,"shoe_size":1},{"player_id":2,"shoe_size":2},

What to do next after I get the saved value?

if(localStorage["player"]){
    player = JSON.parse(localStorage["player"]);
}

Satpal · Accepted Answer · 2015-06-01 08:20:44Z

1

You can use .filter()

The filter() method creates a new array with all elements that pass the test implemented by the provided function.

player  = player .filter(function( obj ) {
    return !(obj.player_id == 2 && obj.shoe_size == 1);
});

If you want to set it:

localStorage["player"] = JSON.stringify(player)

var player = [{"player_id":1,"shoe_size":3},{"player_id":2,"shoe_size":1},{"player_id":2,"shoe_size":2}];

player  = player.filter(function(obj) {
    return !(obj.player_id == 2 && obj.shoe_size == 1);
});

document.write(JSON.stringify(player))

edited Jun 1, 2015 at 8:20

answered Jun 1, 2015 at 8:11

Satpal

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4 Comments

Aaron Musktin Over a year ago

is filter a jquery function or pure js?

Aaron Musktin Over a year ago

can it be this.player_id instead of obj.player_id?

Aaron Musktin Over a year ago

yes,thanks so much! but can I it use map or grep? What's the advantage of using filter()?

Phylogenesis Over a year ago

@AaronMusktin Array.prototype.map() returns one element for every element in the original array. Array.prototype.filter() returns only the specific elements that return true in the function provided. They are used in different situations.

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