Cannot bind argument to parameter "FilePath" because it is null

Question

Every time I run the script below I get

Cannot bind argument to parameter 'FilePath' because it is null.

It was working last night. No changes have been made and this morning it just fails. the funny thing is if i save the script and then run it, it works. However if I clear console then run it again it fails.

Am I missing something obvious?

New-Item -ItemType Directory -Force -Path C:\NonStandard_Services
set-location C:\NonStandard_Services 
$Computers= Get-Content C:\computers.txt
$Report= $file
$file= $Computer
ForEach ($Computer in $Computers)
{
Get-WmiObject -ComputerName $Computer -class Win32_Service -ErrorAction SilentlyContinue | 
Where-Object -FilterScript {$_.StartName -ne "LocalSystem"}|
Where-Object -FilterScript {$_.StartName -ne "NT AUTHORITY\NetworkService"} | 
Where-Object -FilterScript {$_.StartName -ne "NT AUTHORITY\LocalService"} |
Select-Object -Property StartName,Name,DisplayName|
    ConvertTo-Html -Property StartName,Name,DisplayName -head $HTML -body "<H2>Non-    Standard Service Accounts on $Computer</H2>"| Out-File $Report -Append}
    #Rename-Item c:\GP_Services\Report.htm $file 
    Get-ChildItem | Where-Object {$_.extension -ne ".htm"} | Rename-Item -newname { $_.name + '.htm' }

Error is Out-File : Cannot bind argument to parameter 'FilePath' because it is null. At C:\Users\adminrrahul\Desktop\Svc_Accs Final03.ps1:14 char:135 + ... H2>"| Out-File $Report -Append} + ~~~~~~~ + CategoryInfo : InvalidData: (:) [Out-File], ParameterBindingValidationException + FullyQualifiedErrorId : ParameterArgumentValidationErrorNullNotAllowed,Microsoft.PowerShell.Commands.OutFileCommand — Norrin Rad
– Norrin Rad, Commented Jun 5, 2015 at 10:38

Ansgar Wiechers · Accepted Answer · 2015-06-05 14:13:47Z

4

$Report= $file
$file= $Computer
ForEach ($Computer in $Computers)
{
  ...
}

You assign variables to other variables before they were assigned a value themselves. Change the above to this:

ForEach ($Computer in $Computers) {
  $file   = $Computer
  $Report = $file
  ...
}

Or directly use $Computer in Out-File:

... | Out-File "$Computer.txt" -Append

edited Jun 5, 2015 at 14:13

answered Jun 5, 2015 at 10:54

Ansgar Wiechers

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