PHP - Compare a string to all in array and only echo once (unique)

Question

I'm trying to make a list of directories from a file. But I only want the list to contain unique entries i.e. - only echo once no duplicates.

Example: From this log file:

inactive : [2007-04-01 08:42:21] "home/club/member" 210.00 "r-200"
inactive : [2008-08-01 05:02:20] "home/club/staff" 25.00 "r-200"
active : [2010-08-11 10:12:20] "home/club/member" 210.00 "r-500"
inactive : [2010-01-02 11:12:33] "home/premier/member" 250.00 "r-200"
active : [2013-03-04 10:02:30] "home/premier/member" 250.00 "r-800"
active : [2011-09-14 15:02:55] "home/premier/member" 250.00 "r-100"

I want to echo the list of directories but no duplicates:

home/club/staff

home/club/member

home/premier/member

I used a foreach loop to iterate through the array but I don't know how to compare each value to each item in the array and then only output identical items once.

foreach($listofDir as $value) 
{
    echo "<p>" . $value .  "</p>";
}

possible duplicate of php - find if an array contains an element — Risadinha
– Risadinha, Commented Jun 14, 2015 at 11:04

Rizier123 · Accepted Answer · 2015-06-14 11:04:14Z

1

This should work for you:

Just get your file into an array and then grab the paths out of each line.

<?php

    $lines = file("test.txt", FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES);

    $directorys = array_unique(array_map(function($v){
        preg_match("/.*? : \[.*?\] \"(.*?)\"/", $v, $m);
        return $m[1];
    }, $lines));

    print_r($directorys);

?>

output:

Array
(
    [0] => home/club/member
    [1] => home/club/staff
    [3] => home/premier/member
)

answered Jun 14, 2015 at 11:04

Rizier123

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2 Comments

Maurice Greenland Over a year ago

Thanks, which part of that script ensures I'm not outputting an identical value?

Rizier123 Over a year ago

@MauriceGreenland array_unique() So that you only have unique values

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