Passing php variables through the parameter to a javascript trigger function, PHP, JAVASCRIPT

Question

I'm trying to pass 2 variables through a php function's parameters to be use by the javascript's trigger function but the javascript's trigger function is not accepting the 2 variables. Not sure what I did wrong. Please take a look:

trigger.php

<?php

function trigger($type,$name) {

echo "<script>";

echo "

$(function(){
  $('$type[name=$name]').trigger('change');
});

";

echo "</script>";

}

?>

@cmorrissey Parse error: syntax error, unexpected '=', expecting ']' — frosty
– frosty, Commented Jun 17, 2015 at 18:23
@cmorrissey I assume it's talking about the name=$name, part. But not sure what I did wrong there. — frosty
– frosty, Commented Jun 17, 2015 at 18:24
try to escape $(function(){ to \$(function(){ and $('$type[name to \$('$type[name ?I'm not sure the $ can be escaped or not. — fuyushimoya
– fuyushimoya, Commented Jun 17, 2015 at 18:27

cmorrissey · Accepted Answer · 2015-06-17 18:29:59Z

2

The problem is that you are using " which attempt to parse the variables in the string, if you switch to ' the $ of the jQuery won't be parsed and you can concat your variables with .

function trigger($type,$name) {

echo '<script>';

echo '

$(function(){
  $(\'' . $type . '[name=' . $name . ']\').trigger(\'change\');
});

';

echo '</script>';

}

answered Jun 17, 2015 at 18:29

cmorrissey

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1 Comment

frosty Over a year ago

Thanks for the answer! It works. I have to admit, at this point it gets really confusing when mixing php and javascript types into a single function.

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