Bash: use parameters of function to do a grep search

Question

I am trying to create a function that will take the parameters that I pass it and do a grep search in my current directory, but I can't figure out how to use all the parameters as one string.

Here is what I have:

search()
{
  clear
  grep -rnw . -e $("\"" $@ "\"")
}

So if I were to type, search title =, I would want it to do grep -rnw . -e "title ="

Any ideas for how to do this?

how do would I make it so I can use other characters without quotes? such as > or " or other escape characters? — kmoney42
– kmoney42, Commented Jun 24, 2015 at 21:29

anubhava · Accepted Answer · 2015-06-23 19:34:50Z

1

Use "$*" if you want all passed arguments as a single string:

search() {
  clear
  grep -rnw "$*" .
}

answered Jun 23, 2015 at 19:34

anubhava

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