Pass function output to find the string passed as argument into function output from input file

Question

I have a simple function which will give me past one hour log

past_hour_log(){
    awk -v Date1=$(date -d"now 1 hour ago" "+%H:%M:%S") -v Date2=$(date -d"now 1 hour ago" "+%d") ' { if ($3 > Date1 && $2 >= Date2) {print $0}} ' /var/log/syslog
}

My function Output :

Oct  9 12:15:15 localhost-IdeaPad-980 systemd[1]: time has been changed
Oct  9 12:16:00 localhost-IdeaPad-980 systemd[1534]: time has been changed
Oct  9 12:17:00 localhost-IdeaPad-980 systemd-timesyncd[25237]: Synchronized to time server 91.189.91.157:123 (ntp.ubuntu.com).
Oct  9 12:17:01 localhost-IdeaPad-980 CRON[27685]: (root) CMD (   cd / && run-parts --report /etc/cron.hourly)
Oct  9 12:17:01 localhost-IdeaPad-980 CRON[29613]: (root) CMD (   cd / && run-parts --report /etc/cron.hourly)

So here on next line, I am trying to pass this function output into grep xargs to get a total count of the string given as input from input.txt

TIME_COUNT="$(cat input.txt | xargs -I{} grep {} past_hour_log | awk '{print $7}' | awk -F '?' '{print $1}' | uniq -c)"

But the output shows me below. Are there any ideas to achieve this?

grep: past_hour_log: No such file or directory

@Inian: Kindly understand the description given and mark as duplicate. — Sri
– Sri, Commented Oct 9, 2018 at 7:14
Your requirement is an exact duplicate of the one I've given. Just export your function as export -f past_hour_log before calculating TIME_COUNT — Inian
– Inian, Commented Oct 9, 2018 at 7:16
I try export but the error i get 'export: Illegal option -f' — Sri
– Sri, Commented Oct 9, 2018 at 7:29
I need some exact solution for my question how this can be used. I am new to shell. — Sri
– Sri, Commented Oct 9, 2018 at 7:34
First of all, I see some serious quoting problems in your function past_hour_log. Could you fix those first and come back to us? — kvantour
– kvantour, Commented Oct 9, 2018 at 12:37

kvantour · Accepted Answer · 2018-10-09 12:53:21Z

1

You might want to attempt the following:

past_hour_log() {
    date1=$(date -d"now 1 hour ago" "+%H:%M:%S")
    date2=$(date -d"now 1 hour ago" "+%d")
    awk -v Date1="$date1" -v Date2="$date2" '($3 > Date1 && $2 >= Date2){print}' /var/log/syslog;
}

and then do

TIME_COUNT="$(past_hour_log | grep -F -f input.txt | awk '{print $7}' | awk -F '?' '{print $1}' | uniq -c)"

answered Oct 9, 2018 at 12:53

kvantour

26.9k4 gold badges57 silver badges81 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Sri Over a year ago

Kindly refer this issue: stackoverflow.com/questions/52772238/…

Collectives™ on Stack Overflow

Pass function output to find the string passed as argument into function output from input file

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related