Url pattern for alphanumeric(slug) string in django

Question

I am trying to make this url patterns work, but I am not getting anywhere.I get a page not found error.The url in my url bar is http://127.0.0.1:8000/tags/?Pythonif I select python slug, but it does not use the defined url. What I want to do is, open a new template with information related to slug. This is my view:

def tags(request,slug):
    verse = get_object_or_404(Tag, slug=slug)
    return render(request, 'tags.html',{'verse':verse})

Here is my url:

 url(r'^tags/(?P<slug>[\W-]+)/$', views.tags),

This is my template:

Tagged under -  {% for i in verse.tags.all%}<a href='/tags'>{{ i }} | </a>{% endfor %}

I have tried passing a query string in template as:

/tags/q={{i}}

I have also tried to use:

{% url tags i.slug %}

(based on Slug Url Regex in Django)

But so far nothing is working. I want to open the tags template with the selected slug being displayed.

What is in views.tags? Also [\W-] can be replaced with \W since - is already matched with \W in Python. — Andie2302
– Andie2302, Commented Jul 4, 2015 at 3:08
@Andie2302 views.tags is the view that renders the tags template. — ESS
– ESS, Commented Jul 4, 2015 at 3:10

M.javid · Accepted Answer · 2015-07-07 05:22:09Z

7

you must set a name In url similar below:

url(r'^tags/(?P<slug>.+)/$', views.tags, name='tags'),

in template change your url tag to:

{% url "tags" slug=i.slug %}

edited Jul 7, 2015 at 5:22

answered Jul 4, 2015 at 5:13

M.javid

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2 Comments

ESS Over a year ago

Now i am getting NoReverseMatch at / Reverse for 'tags' with arguments '()' and keyword arguments '{u'slug': u'Python'}' not found. 1 pattern(s) tried: ['tags/(?P<slug>\\W+)/$']

ESS Over a year ago

got it in the end. The problem was with my url too. I had to remove the [\W-] and replace it with a . to make it work

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