Selenium wait for keypress, python

Question

I want selenium to open page and wait for keypress, based on key pressed script should do different actions. It seems there is no Expected Conditions for this case, how can I write my own?

Here is pseudo code:

driver.get('http://google.com')
# wait for keypress
# if keypress == ARROW_RIGHT:
#     print "ARROW_RIGHT"
# elif keypress == ARROW_LEFT:
#     print "ARROW_LEFT"

Community · Accepted Answer · 2017-05-23 11:51:14Z

1

You will need to use a python method to check for a key press input. There are different ways to do this depending on if you are using a GUI support library or not. Take a look at this answer, which covers multiple ways on how to work with key presses.

After you detected a key press you can continue performing your task in Selenium.

edited May 23, 2017 at 11:51

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answered Jul 6, 2015 at 23:33

DJanssens

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1 Comment

jumps4fun Over a year ago

This seems like the right answer to accept. I don't claim to have a full overview of seleniums API, but bear in mind that it is an automatic testing library, and that manual inputs are probably out of scope.

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