Accessing values in Swift 1.2 multi-dimensional arrays

Question

Apologies in advance. I am a newbie learning Swift and have some working experience with C and Ruby. I'm venturing into Swift.

I'm trying to create and access a multi-dimensional array as follows:

var arrayTest: [[(Int, Int, Int, String)]] = []
arrayTest.append([(1, 2, 3, "Test")])
arrayTest.append([(4, 5, 6, "Test1")])

This seems to work fine in Playground. But trying to access as follows does not work:

println(arrayTest[0][0])

I looked at several entries and the Apple Swift docs. But I was still unable to figure this out.

Any insights appreciated. Thank you.

Ken Garber · Accepted Answer · 2015-07-21 00:17:34Z

1

Looks like you're trying to make an array of tuples but have an extra set of brackets, meaning you're making an array of arrays of tuples. Also, you append a tuple without putting it in parenthesis. Try:

var arrayTest: [(Int, Int, Int, String)] = []
arrayTest.append(1, 2, 3, "Test")
arrayTest.append(4, 5, 6, "Test1")

You would access an element a little differently. Square brackets return the tuple in arrayTest, and the period returns an element of the tuple.

println(arrayTest[0].0)

This would return 1 (the 0th element of the 0th tuple).

answered Jul 21, 2015 at 0:17

Ken Garber

517 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Accessing values in Swift 1.2 multi-dimensional arrays

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related