How to have WebDriverWait return element instead of boolean in Python using Selenium

Question

Right now, I have a method that will wait until an element is visible using:

WebDriverWait(self.driver, seconds).until(lambda s: s.find_element_by_xpath(path).is_displayed())

This works properly; however, it returns a boolean, rather than the element that it found. I would like it to return that element once it is found. I am doing this with the following:

def waituntil(path, seconds):
    WebDriverWait(self.driver, seconds).until(lambda s: s.find_element_by_xpath(path).is_displayed())
    ret = self.driver.find_element_by_xpath(path)
    return ret

Sure, this works. Unfortunately, it requires Selenium to find the same element twice, though, which adds waiting time (no matter how small). Is there a way I can return a web element using a waituntil (or similar functionality) by finding an element only once? So something that would allow the following:

ret = WebDriverWait(self.driver, seconds).until(lambda s: s.find_element_by_xpath(path).is_displayed())
ret.click()

I'm currently using:

Python 2.7
Windows 7
Selenium 2.4.4
Firefox 35.0.1

myersjustinc · Accepted Answer · 2015-08-17 18:41:25Z

1

Use selenium.webdriver.support.expected_conditions.presence_of_element_located.

Based on the unofficial docs:

from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions
ret = WebDriverWait(self.driver, seconds).until(
    expected_conditions.presence_of_element_located((By.XPATH, path)))
ret.click()

(Left out other imports and initialization for clarity, since you seem to have that stuff working. See the earlier link if you're running into issues.)

answered Aug 17, 2015 at 18:41

myersjustinc

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