In Python, how can I check that a string does not contain any string from a list?

list = ['admin', 'add', 'swear']
st = 'siteadmin'
if any([x in st for x in list]):print "found"
else: print "not found"

You can use any built-in function to check if any string in the list appeared in the target string

You can do this by using list-comprehessions

ls = [item for item in lst if item in st]

UPD: You wanted also to know position :

ls = [(item,st.find(item)) for item in lst if st.find(item)!=-1]

Result : [('admin', 4)

You can find more information about List Comprehensions on this page

I am assuming the list is very large. So in this program, I am keeping the matched items in a list.

#declaring a list for storing the matched items
matched_items = []
#This loop will iterate over the list
for item in list:
    #This will check for the substring match
    if item in st:
        matched_items.append(item)
#You can use this list for the further logic
#I am just printing here 
print "===Matched items==="
for item in matched_items:
    print item

Is this what you are looking for?

for item in list:
    if item in st:
        print(item)
        break
    else:
        print("No string in list was matched")

for x in list:
     loc = st.find(x)
     if (loc != -1):
          print x
          print loc

string.find(i) returns the index of where the substr i begins in st, or -1 on failure. This is the most intuitive answer in my opinion, you can make this probably into a 1 liner, but I'm not a big fan of those usually.

This gives the extra value of knowing where the substring is found in the string.