Pointer array is forcing programme to crash

Question

I wanted to pass an array pointer to a function and show content of that array from that function.I did this in below way but when i run the code the whole program is crashing.Please help me or give me idea how to solve this problem...

  int main()
    {
        int size,i;
        cout<<"Please enter the size of the array";
        cin>>size;
        int *array_=new int [size];
        cout<<"Please enter all elements of the array";
        for(i=0;i<size;i++){
            cin>>array_[i];
        }
        insertion(&array_,size);
        return 0;
    }
    void insertion(int *array_[],int size){
        int i;
        for(i=0;i<size;i++){
            cout<<*array_[i];
        }
    }

You are passing the address of a pointer variable here: insertion(&array_,size);. As you want to pass the pointer just change to: insertion(array_,size); — πάντα ῥεῖ
– πάντα ῥεῖ, Commented Sep 15, 2015 at 14:35
@TanvirRahman Well, the signature of insert() is also wrong, should be void insertion(int *array_,int size){. Otherwise it expects an array of pointers. — πάντα ῥεῖ
– πάντα ῥεῖ, Commented Sep 15, 2015 at 14:43

Tanvir Rahman · Accepted Answer · 2015-09-15 15:52:40Z

2

void insertion(int *array_,int size){
    int i;
    for(i=0;i<size;i++){
        cout<<array_[i]<<" ";
    }
}

edited Sep 15, 2015 at 15:52

answered Sep 15, 2015 at 14:43

Tanvir Rahman

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3 Comments

rozina Over a year ago

I think the way you did it was correct as well, although not used very often. However operator[] has precedence over operator*, so the correct code would be cout << (*array_)[i].

Tanvir Rahman Over a year ago

Thanks it is working in your way also.If you want, you can write it in answer section.I will accept is as answer of this question...:)

πάντα ῥεῖ Over a year ago

@TanvirRahman, @rozina I would certainly downvote such answer, because it's totally confusing and not necessary. Stay with what you have now.

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