Removing invisible characters from the end of a Java String

Question

how can i find the last visible character in a Java String? I'd like to remove all line breaks and other invisible characters from a Java String

Kind Regards, Tord

use a regex expression

ergonaut
– ergonaut

2015-09-20 22:42:14 +00:00
Commented Sep 20, 2015 at 22:42 — ergonaut
– ergonaut, Commented Sep 20, 2015 at 22:42
Look at this answer

Javier Haro
– Javier Haro

2015-09-20 22:47:09 +00:00
Commented Sep 20, 2015 at 22:47 — Javier Haro
– Javier Haro, Commented Sep 20, 2015 at 22:47

user3320657 · Accepted Answer · 2015-09-20 22:46:10Z

13

string_variable.replaceAll("\\p{C}", "?");

This will replace all non-printable characters. Where p{C} selects the invisible control characters and unused code points.

answered Sep 20, 2015 at 22:46

user3320657

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sunyata Over a year ago

Thank you for your help, unfortunately this will remove all characters, i'm trying to find the last visible character in an article (like maybe a period or a letter or a number). Then i can remove the rest of the characters that are coming after that

Mick Mnemonic · Accepted Answer · 2015-09-20 22:49:37Z

4

You can use the trim() method of the String class for removing trailing (and leading) white space and line breaks:

String trimmed = original.trim();

edited Sep 20, 2015 at 22:49

answered Sep 20, 2015 at 22:44

Mick Mnemonic

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1 Comment

Cumulo Nimbus Over a year ago

trim does not remove '\u200B' (zero width space). which is the problem I was having. Using .replaceAll("\\p{C}", "?") from the more upvoted answer worked for me

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