Extracting numbers from a string in python 1.5.2

Question

I'm currently working with a Telit module (GT864-py) and I'm trying to extract numbers from a return value/string that I recieve when using AT-commands.

This is an example of the code that I'm using:

MDM.send('AT#ADC=1,2'+'\r', 5)
pump = MDM.receive(15)
pumpb = int(filter(str.isdigit, pump))

which gives the response

#ADC: 10 (This number can range from ~10-150)
OK

Now, I would like to filter the number after ADC, however, I have not yet found a solution as to how.

By using this code in PythonWin 1.5.2+ I get the following error:

NameError: isdigit

So I am assuming isdigit isn't supported in Python 1.5.2, is that correct? And if so, does anyone know any other ways to extract the numbers after #ADC: xxx ?

Why are you using 1.5.2? You could write your own isdigit using all, I suppose. — jonrsharpe
– jonrsharpe, Commented Oct 19, 2015 at 11:23
I guess you will have more success if you contact Python's IRC channel if you want to find users that have experienced this ancient Python version first hand. — Kijewski
– Kijewski, Commented Oct 19, 2015 at 11:24
IIRC Python 1.5.2 already had regexps... But really, Python 1.5.2 ??? That was early 1999 or so ? — bruno desthuilliers
– bruno desthuilliers, Commented Oct 19, 2015 at 11:36
The reason that I am using Python 1.5.2 is that the Telit module itself has a built-in python v 1.5.2 interpreter which, unfortunately, can't be updated to a later version. If it had a later version, say 2.7, this would have been a lot easier but now I'm left with trying to figure out a way to make it work on this old, obsolete piece of machinery — Chris
– Chris, Commented Oct 19, 2015 at 12:09

Antti Haapala · Accepted Answer · 2015-10-19 11:45:52Z

2

The Python 1.5.2p2 documentation is available online. Indeed, there is no isdigit in either str or in the module string.

Even in Python 1.5, str is a sequence that supports the in operation, so you could do:

def isdigit(c):
    return c in '0123456789'

pumpb = int(filter(isdigit, pump))

For more thorough parsing I'd use a regular expression, with module re instead; the code

import re
match = re.search('#ADC:\s*(\d+)', pump)
if match:
    number = match.group(1)

This will match #ADC: followed by any number of spaces, followed by 1 or more digits [0-9]; the digits are captured in the group 1, whose value is then stored to number if a match was found.

edited Oct 19, 2015 at 11:45

answered Oct 19, 2015 at 11:36

Antti Haapala

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1 Comment

Chris Over a year ago

After initial testing, this seems to work perfectly.I will try it more extensively with different numbers later but for now, a big thanks to you Mr. Haapala

RemcoGerlich · Accepted Answer · 2015-10-19 11:41:00Z

0

If the string is always exactly "#ADC: ", then simple string slicing should also work:

if pump[:6] == '#ADC: ':
    pumpb = int(pump[6:])

answered Oct 19, 2015 at 11:41

RemcoGerlich

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