About Switch Case in Bash Script

Question

I'm newbie in bash script, I want to create a switch case without "break" like java code below

switch(choice) {
    case 1: 
           System.out.println("1");
    case 2:
           System.out.println("2");
}

choice = 1

output: 1
        2

so ... how can I do that in bash script :(

chepner · Accepted Answer · 2015-10-21 04:14:31Z

2

Prior to bash 4, you couldn't; at most one block of commands in a case statement would be executed. bash 4 introduced the ;& case terminator, which causes fall-through.

case $choice in
    1) echo 1 ;&
    2) echo 2 ;;
esac

answered Oct 21, 2015 at 4:14

chepner

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5 Comments

Jonathan Leffler Over a year ago

@hoaithy92: if you run bash --version, is it version 3.x or 4.x?

hoaithy92 Over a year ago

@JonathanLeffler it version is 4.3.1

Jonathan Leffler Over a year ago

@hoaithy92: OK; that should support the case … esac notation that @chepner showed. The switch notation you showed doesn't apply to Bash; it might be valid in C shell, or something similar might be valid (I neither know nor care).

hoaithy92 Over a year ago

So that no way to do like switch that I showed, right ? :(

cuonglm Over a year ago

@hoaithy92: try calling your script with bash, maybe you had called it with sh or its shebang is /bin/sh instead of /bin/bash, and your /bin/sh wasn't linked to /bin/bash.

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