Call Python Function with Opencv in Django

Question

I have a python function for face recognition. I am uploading image with django. and in django given to me a path of image. So i want to call the python function for send a path to function. This python function is making face recognition and return to recognition image path. So i want to call this python function in django. Then I can show as in django.

My post method:

def list(request):
    # Handle file upload
    if request.method == 'POST':
        form = DocumentForm(request.POST, request.FILES)
        if form.is_valid():
            newdoc = Document(docfile = request.FILES['docfile'])
            newdoc.save()

            # Redirect to the document list after POST
            return HttpResponseRedirect(reverse('list'))
    else:
        form = DocumentForm() # A empty, unbound form

    # Load documents for the list page
    documents = Document.objects.all()

    # Render list page with the documents and the form
    return render_to_response(
        'myapp/list.html',
        {'documents': documents, 'form': form},
        context_instance=RequestContext(request)
    )`

list.html:

    <!-- List of uploaded documents -->
            {% if documents %}

                    {% for document in documents %}
                    <article class="one_quarter" style="margin-bottom:6px;">
                        <figure>
                            <img src="{{ document.docfile.url }}" width="215" height="315" alt="{{ document.docfile.name }}">
                           <figcaption>Adsız</figcaption>
                        </figure>
                    </article>
                    {% endfor %}

            {% else %}
                    <p>Resim Bulunamadı</p>
            {% endif %}
            <div>
            <!-- Upload form. Note enctype attribute! -->
            <form action="{% url "list" %}" method="post" enctype="multipart/form-data">
                    {% csrf_token %}
                    <p>{{ form.non_field_errors }}</p>
                    <p>{{ form.docfile.label_tag }} </p>
                    <p>
                            {{ form.docfile.errors }}
                            {{ form.docfile }}
                    </p>
                    <p><input type="submit" value="Upload" /></p>

When i was uploading image, This python function take to image path and test image folder path, then should return to image path of recognition. Then i want to show which image path returned.

Python libraries :

import cv2, os
import numpy as np
from PIL import Image

and function definition in python:

def get_face_recog(path, image_path)
    ...
    return frimage

Could you explain a little more what you want to do? Can you provide a sample of the template you want to use and what you want to get back? — Foon
– Foon, Commented Oct 28, 2015 at 12:51
Actually i have a python function as i said. I am uploading image with django. and in django given to me a path of image. So i want to call the python function for send a path to function. This python function is making face recognition and return to recognition image path. So i want to call this python function in django. Then I can show as <img src="path from python function"> in django. — Gkan
– Gkan, Commented Oct 28, 2015 at 13:11

Alasdair · Accepted Answer · 2015-10-28 13:40:10Z

1

The easiest way to call a python function is in your view, not your template. You could do something like:

def my_view(request):
    image_url = get_face_recog(path, image_path)
    return render(request, 'mytemplate.html', {'image_url': image_url})

Then in your template:

<img src="{{ MEDIA_URL }}{{ image_url }}" />

If you really need to call the function from your template, you could write a custom tag or filter.

You'll need to configure your MEDIA_ROOT and MEDIA_URL settings, and make sure that your server is serving the directory that the images are in.

edited Oct 28, 2015 at 13:40

answered Oct 28, 2015 at 13:20

Alasdair

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7 Comments

Foon Over a year ago

shouldn't that be <img src="{{ image_url}}">?

Foon Over a year ago

Also, maybe I'm overthinking it, but don't you need to apply a static or media tag so that it will convert from location on disk to how that URL is served via the web browser?

Alasdair Over a year ago

@Foon Yes, there will be some configuration required to serve the image. The point I was trying to make is that the best place to call a python function is the view, not the template.

Gkan Over a year ago

How can i do this for post method ? i am uploading image then i can take a path of image, i want to send image path to function, then it will return recognition image path then i can show recognition image path.

Alasdair Over a year ago

Please update your question with what you've tried so far for your post method, and explain what the problem is.

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