I am trying to step through a thread. This works while I use debugger.SetAsync(False), but I want to do this asynchronously. Here is a script to reproduce it. It steps when setting debugger.SetAsync (False) instead of True. I added time.sleep so that it has time to execute my instructions. I expect the next instruction in the frame.pc
import time
import sys
lldb_path = "/Applications/Xcode.app/Contents/SharedFrameworks/LLDB.framework/Resources/Python"
sys.path = sys.path + [lldb_path]
import lldb
import os
exe = "./a.out"
debugger = lldb.SBDebugger.Create()
debugger.SetAsync (True) # change this to False, to make it work
target = debugger.CreateTargetWithFileAndArch (exe, lldb.LLDB_ARCH_DEFAULT)
if target:
main_bp = target.BreakpointCreateByName ("main", target.GetExecutable().GetFilename())
print main_bp
launch_info = lldb.SBLaunchInfo(None)
launch_info.SetExecutableFile (lldb.SBFileSpec(exe), True)
error = lldb.SBError()
process = target.Launch (launch_info, error)
time.sleep(1)
# Make sure the launch went ok
if process:
# Print some simple process info
state = process.GetState ()
print 'process state'
print state
thread = process.GetThreadAtIndex(0)
frame = thread.GetFrameAtIndex(0)
print 'stop loc'
print hex(frame.pc)
print 'thread stop reason'
print thread.stop_reason
print 'stepping'
thread.StepInstruction(False)
time.sleep(1)
print 'process state'
print process.GetState ()
print 'thread stop reason'
print thread.stop_reason
frame = thread.GetFrameAtIndex(0)
print 'stop loc'
print hex(frame.pc) # invalid output?
Version: lldb-340.4.110 (Provided with Xcode)
Python: Python 2.7.10
Os: Mac Yosemite