@TestPropertySource with dynamic properties

Question

I am using @TestPropertySource to overwrite application.yml properties in my integration test for a spring boot app.

@TestPropertySource(properties = { "repository.file.path=src/test/resources/x" })

I was wondering if there was some way to make the property VALUE dynamic. Something like this:

 @TestPropertySource(properties = { "repository.file.path=PropertyValueProvider.class" })

Your feedback is appreciated. In my case the property value is system specific that should be generated upon the test run.

Oliver Drotbohm · Accepted Answer · 2019-02-13 15:37:12Z

28

@TestPropertySource only provides declarative mechanisms for configuring PropertySources. Documentation in Spring Reference Manual.

If you need programmatic support for adding a PropertySource to the Environment, you should implement an ApplicationContextInitializer which can be registered via @ContextConfiguration(initializers = ...). Documentation in Spring Reference Manual.

Regards,

Sam (author of the Spring TestContext Framework)

edited Feb 13, 2019 at 15:37

Oliver Drotbohm

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answered Jun 24, 2016 at 12:20

Sam Brannen

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3 Comments

barfuin Over a year ago

I found this example to show how it is done in practice.

chrismacp Over a year ago

@barfuin - This looks like exactly what i need...except I'm using Boot v1.5 and that example uses features (TestPropertyValues) introduced in 2.0. Don't suppose anyone would have any other examples?

Sam Brannen Over a year ago

In Spring Boot 1.5.x you can use the properties attribute of @SpringBootTest: docs.spring.io/spring-boot/docs/1.5.21.BUILD-SNAPSHOT/api/org/…

Raedwald · Accepted Answer · 2023-04-23 19:42:52Z

14

You can also do this with the @DynamicPropertySource annotation in Spring Boot 5.2. This enables you to set the property value programmatically (dynamically).

See: https://github.com/spring-projects/spring-framework/issues/24540

Add this to your integration test class:

@DynamicPropertySource
static void dynamicProperties(DynamicPropertyRegistry registry) {
  registry.add("my.property", () -> {
       // some logic to get your property dynamically
   });
}

edited Apr 23, 2023 at 19:42

Raedwald

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answered Jan 7, 2022 at 22:49

Amrit Baveja

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1 Comment

Felipe Over a year ago

How would you do if you want to test with 2 or more values in my.property?

lance-java · Accepted Answer · 2021-11-05 10:17:27Z

I did this thanks to Sam Brannen's answer

Here's the sample code:

@ContextConfiguration(classes = { MyConfiguration.class }, initializers = { MyInitializer.class })
public class MyContextConfiguration {
    public static class MyInitializer implements ApplicationContextInitializer<ConfigurableApplicationContext> {
        @Override
        public void initialize(ConfigurableApplicationContext applicationContext) {
            String userNameLower = System.getProperty("user.name").toLowerCase();
            Map<String, Object> dynamicProperties = Map.of("user.name.lower", userNameLower);
            MapPropertySource propertySource = new MapPropertySource("dynamic", dynamicProperties);
            applicationContext.getEnvironment().getPropertySources().addLast(propertySource);
        }
    }

    @Configuration
    @PropertySource("classpath:my-static.properties") // properties in this file can reference ${user.name.lower}
    public static class MyConfiguration {
        @Bean
        public MyBean myBean(@Value("${user.name.lower}") String userNameLower) {
            return new MyBean(userNameLower);
        }
    }
}

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