CakePHP 3 : Image upload from controller

Question

I am trying to uploading image from controller using PHP. Here image upload is working fine but content is not saving in database, only image path saving. If I comment on image upload code then content is add in database fine.

Here is my code that I have tried

    <?= $this->Form->create($news,array('type'=>'file')) ?>
             <div class="col-md-12">
                <?php
                    echo $this->Form->input('newsImage',['type'=>'file']);
                    echo $this->Form->input('title',['class'=>'form-control']);
                    echo $this->Form->input('news');
                ?>
            </div>
   <?= $this->Form->end() ?>

And in controller I have tried below code for upload image

 if ($this->request->is('post')) {

                $target_dir = "img/news/";
                $target_file = $target_dir . basename($_FILES["newsImage"]["name"]);

                $fNAME   = $_FILES["newsImage"]["name"];
                $TMPNAME = $_FILES['newsImage']['tmp_name'];

                move_uploaded_file($_FILES["newsImage"]["tmp_name"], $target_file);


                $this->request->data['News']['newsImage']=$fNAME;

                $news = $this->News->patchEntity($news, $this->request->data);
                if ($this->News->save($news)) {
                    $this->Flash->success(__('The news has been saved.'));
                    //return $this->redirect($this->referer()); 
                    return $this->redirect(['action' => 'index']);
                } else {
                    $this->Flash->error(__('The news could not be saved. Please, try again.'));
                }
}

Here only image directory saving in database, title and news not saving.

I don't think you want that ['News'] level in the data. Take a look at the contents of $this->request->data and match fields that you create to that format. — Greg Schmidt
– Greg Schmidt, Commented Dec 18, 2015 at 7:21

Alimon Karim · Accepted Answer · 2016-02-14 09:24:57Z

1

There has only one problem,

$this->request->data['News']['newsImage']=$fNAME;

To

$this->request->data['newsImage']=$fNAME;

In cakephp 3 you don't need define model name. You can use browser inspector element to see field name, then match between cakephp-2 and cakephp 3 form then you can see the changed.

edited Feb 14, 2016 at 9:24

answered Feb 11, 2016 at 5:10

Alimon Karim

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Community · Accepted Answer · 2020-06-20 09:12:55Z

$this->request->data['newsImage']=$fNAME;

After this add this line

$news=$this->News->newEntity();

After add this code ur controller looks like:

if ($this->request->is('post')) {
   $target_dir = "img/news/";
   $target_file = $target_dir . basename($_FILES["newsImage"]["name"]);

   $fNAME   = $_FILES["newsImage"]["name"];
   $TMPNAME = $_FILES['newsImage']['tmp_name'];

   move_uploaded_file($_FILES["newsImage"]["tmp_name"], $target_file);


   $this->request->data['newsImage']=$fNAME;

   $news=$this->News->newEntity();
   $news = $this->News->patchEntity($news, $this->request->data);
   if ($this->News->save($news)) {
       $this->Flash->success(__('The news has been saved.'));
       //return $this->redirect($this->referer()); 
       return $this->redirect(['action' => 'index']);
   } else {
        $this->Flash->error(__('The news could not be saved. Please, try again.'));
   } 
}

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