parsing command line output on Windows command line batch file

Question

I have this command that scan a file and returns a summary.

For example on running this command

omsCmdLineUtil.exe process C:\test.exe Default

the result output is:

Ticket:[ 2214271306 ]

Process Details
---------------


File: [ C:\test.exe ]
   MD5: [ D41D8CD98F00B204E9800998ECF8427E ]
   SHA1: [ DA39A3EE5E6B4B0D3255BFEF95601890AFD80709 ]
   SHA256: [ E3B0C44298FC1C149AFBF4C8996FB92427AE41E4649B934CA495991B7852B855 ]
   File Size: [ 0 bytes ]
   File Type  Category: [ O ]
   File Type: [ - ]
   File Type Description: [ empty ]

[ Clean ] Ahnlab scan engine [ 1 ms ]
[ Clean ] ClamAV scan engine [ 1 ms ]
[ Clean ] BitDefender scan engine [ 1 ms ]
[ Clean ] Avira scan engine [ 1 ms ]
[ Clean ] Quick Heal scan engine [ 1 ms ]
[ Clean ] ThreatTrack scan engine [ 1 ms ]
[ Clean ] ESET scan engine [ 1 ms ]
[ Clean ] Total Defense scan engine [ 1 ms ]

Scan Completion
---------------
        [ Clean ]
        Ticket: [ 2214271306 ]
        File path: C:\test.exe
        Scan time: 1 ms [12/20/2015 13:00:06:791]


Process Completion
------------------
        Ticket: [ 2214271306 ]
        User agent: Default
        Profile: Default
        Result: [ Allowed ]
        File processed: C:\test.exe

I want to create a batch file that parses this result by searching for the output line Result:, check if it's [ Allowed ] or [ Blocked ] and return 0 for allowed and 1 for blocked.

I tried something like this, but its not really working:

omsCmdLineUtil.exe process C:\test.exe Default | set ts = findstr /C:"Result: [ Allowed ]"

if %ts% == "Result: [ Allowed ]" return 0
else return 1

Which modification on code is necessary to get the expected result?

basically, because there is no variable %ts%. You produced one with the Name %ts %. Be carefull with spaces in Batch. — Stephan
– Stephan, Commented Dec 20, 2015 at 12:25
Also, the variable you created is temporary because each side of the pipe is run in a child process. The variable disappears once the pipe is closed. — dbenham
– dbenham, Commented Dec 20, 2015 at 14:23

Stephan · Accepted Answer · 2015-12-20 12:43:50Z

1

there is no return in Batch. I think, you want exit /b <errorlevel>

omsCmdLineUtil.exe process C:\test.exe Default | find "Result: [ Allowed ]" >nul && Exit /b 0 || Exit /b 1

Instead of Exit 0 you can of Course also use set ts=0 and use that. Or use echo instead.

Some explanations:

>nul redirects the output to nirvana, keeping your screen clean.

&& acts as "If previous command was successfull, then..." (string was found)

|| acts as "if previous command was not successfull, then...` (string was not found)

I prefer using find when possible because of it's simpler syntax, but of course findstr /C:"Result: [ Allowed ]"will also work

edited Dec 20, 2015 at 12:43

answered Dec 20, 2015 at 11:30

Stephan

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5 Comments

aschipfl Over a year ago

exit will also terminate the cmd instance the batch file is running in, whereas exit /B only terminates the batch file itself...

dbenham Over a year ago

FIND already returns ERRORLEVEL of 0 for found and 1 for not found, so the conditional EXIT /B statements are redundant. You could simply issue a single EXIT /B (without specifying ERRORLEVEL) and the FIND result will be propagated.

Stephan Over a year ago

@dbenham yes, but better be sure: something like ...||(timeout 5&exit /b) may ruin it.

David Gidony Over a year ago

thank you for all the great answers, i have another sub-question. what if i want to find two lines in the output . is that also easily possible ? thanks

Stephan Over a year ago

findstr is able to do that. See findstr /?

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