Trouble with array_unique

Question

print_r($tokens);
$tokens = array_unique($tokens);
print_r($tokens);

Gives the following output:

Array
(
    [0] => Array
        (
            [Class_ID] => 32709
        )

    [1] => Array
        (
            [Class_ID] => 34682
        )

    [2] => Array
        (
            [Class_ID] => 34818
        )

)
Array
(
    [0] => Array
        (
            [Class_ID] => 32709
        )

)

I don't want it to be changing anything with that array_unique, since the Class_ID values are different.. whats up?

Marcel Korpel · Accepted Answer · 2011-03-17 11:10:16Z

3

From documentation:

Note: Two elements are considered equal if and only if
(string) $elem1 === (string) $elem2
In words: when the string representation is the same. The first element will be used.

All your elements toString are Array.

edited Mar 17, 2011 at 11:10

Marcel Korpel

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answered Aug 10, 2010 at 5:58

Tyler Carter

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5 Comments

Ben G Over a year ago

Ah, didn't know that. I solved it by specifying SORT_NUMERIC on the sort_flag param.

alex Over a year ago

That's correct, you will need to iterate through them with in_array() to see if you have duplicates.

Ben G Over a year ago

@alex, see above i was able to get it with that parameter

Bang Dao Over a year ago

@babonk: that just because you're lucky this time. Let try with array that has some item equa/same as some others.

Ben G Over a year ago

anyone know how i could do this, then?

Ben G · Accepted Answer · 2010-08-11 03:37:47Z

0

Found a function from php.net that does array_unique on multi-dimensional arrays:

function super_unique($array) //array unique for multi 
{
  $result = array_map("unserialize", array_unique(array_map("serialize", $array)));

  foreach ($result as $key => $value)
  {
    if ( is_array($value) )
    {
      $result[$key] = super_unique($value);
    }
  }

  return $result;
}

answered Aug 11, 2010 at 3:37

Ben G

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