How to send HTTP request in SSH?

Question

I'm trying to make a simple HTTP request in Python in an SSH terminal:

from requests import get
r = get("https://www.google.com")

However, this command just stalls to infinity. This does not happen when not in SSH.

Is there any way to send the request such that it goes through?

Thanks ahead of time.

EDIT: Running the logging in Joran's link yields only the following line:

INFO:requests.packages.urllib3.connectionpool:Starting new HTTPS connection (1): www.google.com

your import does not match your code ... this question really doesnt make sense ... it works fine in my ssh terminal (and ever ssh terminal I have ever tried) — Joran Beasley
– Joran Beasley, Commented Feb 4, 2016 at 0:00
@JoranBeasley Fixed; the code I was testing with was correct. — Cisplatin
– Cisplatin, Commented Feb 4, 2016 at 0:03
see stackoverflow.com/questions/10588644/… ... you might be able to see some extra debug info about what is going on — Joran Beasley
– Joran Beasley, Commented Feb 4, 2016 at 0:06
is this a virtualbox? or a physical machine? I would likely blame the network configuration (ie firewall/proxy/or VM network adapter) — Joran Beasley
– Joran Beasley, Commented Feb 4, 2016 at 0:12

Zada Zorg · Accepted Answer · 2016-02-04 00:32:06Z

2

First, check that you have ability to reach URL using some system-wide tool, like curl: curl -I "https://www.google.com". In case, you will have not timeout error, and got success response, my answer is not for you :)

You code can run forever, just because there is not timeout defined for socket connections. And if for some reason your system is not able to read from socket (at low level), you have to wait for long time.

http://docs.python-requests.org/en/latest/user/quickstart/#timeouts

answered Feb 4, 2016 at 0:32

Zada Zorg

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felixbade · Accepted Answer · 2016-02-03 23:59:36Z

1

Try this (assuming you are using python3):

from urllib.request import urlopen
r = urlopen('https://www.google.com').read()

answered Feb 3, 2016 at 23:59

felixbade

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3 Comments

Cisplatin Over a year ago

I was using urlllib2 before and was having the same error, not sure this will work.

Joran Beasley Over a year ago

why do you think this will work if requests wont? @felixbade

felixbade Over a year ago

@JoranBeasley ahh, I thought there was just a typo in the code

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