2

I know this question has been asked a lot and this is going to get flagged as duplicate, but I need the code because I can't get my head around any of it.
I have a variable x in my js file. I want that in my php file. Here's the messed up code that I have:
index.js-

var x=5;
  $.ajax({
  type: 'POST',
  url: 'form.php',
  data: {'variable': x },
});

form.php- 

<?php $myval = $_POST['x'];
echo $myval;?>

Also, do I need to connect with the server first or something for the ajax call? Thanks in advance.

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1
  • 1
    You don't need the ?> and are probably better off without it, might get new line of returned value as is. Commented Feb 4, 2016 at 13:58

3 Answers 3

Reset to default
5

You're adding this POST body 

['variable' => 5]

Why are you then requesting $_POST['x'];?
The index x is undefined and will throw a notice/error.

Something useful you can do (during development only), when you're unsure what is accessible in you're PHP code is dumping the required variable:

<?php 
   var_dump($_POST);
?>
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6 Comments

Thanks for the update @chris85. I'm still new to the formatting within SX.
Might want to look at meta.stackoverflow.com/questions/251361/… for formatting options in the future. It was pretty well formatted already.
Hello people. The 'x' in there was a mistake. I'd written the correct code before and it still showed an "undefined index: variable" error.
Please verify that the correct PHP file is requested by the Ajax request. If so, check the available indexes with var_dump($_POST);
doesn't work. It shows an array of the login data thats present in the same form.php file though. Maybe the stuff isnt referencing properly.
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4

In Ajax data you have sent key:value. So in PHP file you can access it by $_POST['key'].

Here your key is variable and value is x which is 5 So you can access it by $_POST['variable']

Write it as below:-

<?php 
$myval = $_POST['variable'];
echo $myval; // output will be 5
?>

Hope it will help you :)

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7 Comments

Oh sorry about that. I did use this code and it still shows the same error. Undefined index: variable. The code looks alright though. Everything is on my localhost. I have the src tag referring to the js file alright too. Can't figure out what might be the problem
Write this line and check output :- echo '<pre>'; print_r($_POST);
What is your output?
doesn't work. It shows an array of the login data thats present in the same form.php file though. Maybe the stuff isnt referencing properly.
Notice: Undefined index: variable in C:\xampp\htdocs\form.php on line 100 array(3) { ["submitLogin"]=> string(0) "" ["uname"]=> string(5) "navya" ["password"]=> string(8) "wrvwrvwr" }
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1

This ajax call is like this form submit

<form action="form.php" method="POST"> 
<input type="text" name="variable" value="5">
<input type="submit" value="Submit">
</form>

Then in your form.php you will do: 

<?php 
myval = $_POST['variable'];
echo $myval; // output will be 5
?>
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