n-dimensional array python

Question

In python, a 0 filled 2D array can be achieved using:

[[0 for x in range(w)] for y in range(h)]
//where w is the width and h is the height

I was wondering, how could this be done so you could create a function which could return a N dimensional array filled with 0s, where the x,y,z,w etc were specified in an array as a parameter.

Example:

makeNArray(3, [4, 5, 6])
//would make a 3D array which was 4x5x6

I have tried several things involving foor loops and while loops but to no avail — dangee1705
– dangee1705, Commented Feb 17, 2016 at 10:12
You should include some of that in your post along with the results. — Arc676
– Arc676, Commented Feb 17, 2016 at 10:12

dangee1705 · Accepted Answer · 2016-02-17 10:14:53Z

1

After some editing I found that I could do:

def nDimensionalArray(n, s):
    x = 0
    for i in range(n):
        x = [x for j in range(s[i])]
    return x

answered Feb 17, 2016 at 10:14

dangee1705

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1 Comment

holroy Over a year ago

Have you tried changing anything in the array returned from this? You'll see that it doesn't quite behave as expected...

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