SpringMVC url path pattern replacement

Question

I have a url path pattern in SpringMVC which looks like:

/person/{personId}/address/{addressId}

and I have personId = 2 and addressId = 3 Is there an easy way for me to generate

/person/2/address/3

using a utility method within SpringMvc?

MaVVamaldo · Accepted Answer · 2016-02-22 14:07:06Z

5

look at UriTemplate class. you can construct your own UriTemplate from your URL, and then expand the template variables.

UriTemplate template = new UriTemplate("http://example.com/hotels/{hotel}/bookings/{booking}");
Map<String, String> uriVariables = new HashMap<String, String>();
uriVariables.put("booking", "42");
uriVariables.put("hotel", "1");
System.out.println(template.expand(uriVariables));

answered Feb 22, 2016 at 14:07

MaVVamaldo

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