Name mangling in python

Question

Consider the following program.

 class A():
     class __B():
         def __c(self):
             pass
a = A()
dir(a)
['_A__B', '__doc__', '__module__']
dir(a._A__B)
['_B__c', '__doc__', '__module__']

 ^^^^^^^

Why is this not ___B__c why is not there not 3 _s.What is the logic here? According to name mangling,it should be _class and class here is __B.So where are the 2 __s

BrenBarn · Accepted Answer · 2016-02-25 05:40:15Z

4

It's right there in the docs (emphasis added):

Any identifier of the form __spam (at least two leading underscores, at most one trailing underscore) is textually replaced with _classname__spam, where classname is the current class name with leading underscore(s) stripped

answered Feb 25, 2016 at 5:40

BrenBarn

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1 Comment

vks Over a year ago

Do u know If there is any particular reason why python does it or its just the language syntax set that way

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