If array item is empty [duplicate]

Question

I've this array :

Array ( [0] => test1 [1] => test2 [2] => test3 [3] => [4] => test4 )

I want to check if any array item is empty or not, as you can see, there's en empty item into my array : [3] => [4] => test4

So I wrote this condition :

           foreach ($array1 as $value) {

              if(!isset($value)) {
                echo "EMPTY";
              } else {
                echo "Not empty";
             }
          }

But it echo Not empty every time, there must have empty for one item

Thanks for your help !

Please see stackoverflow.com/q/9367450/5470883 I think this answers your question — Alexander Baltasar
– Alexander Baltasar, Commented Mar 10, 2016 at 9:10

Naresh Kumar Nakka · Accepted Answer · 2016-03-10 09:05:45Z

2

You have to check like this:

foreach ($array1 as $value) {
    if ($value) {
        echo "Not empty";
    } else {
        echo "empty";
    }
}

It will display "empty" when there is an empty array or '' or zero value or null. Hope this helps.

answered Mar 10, 2016 at 9:05

Naresh Kumar Nakka

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Comments

Ayaz Ali Shah · Accepted Answer · 2016-03-10 09:05:49Z

0

Php give you empty() function for the task. empty() will determine whether a variable is empty.

 if(empty($value)) {
        echo "EMPTY";
    } else {
        echo "Not empty";
    }

answered Mar 10, 2016 at 9:05

Ayaz Ali Shah

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Comments

Community · Accepted Answer · 2020-06-20 09:12:55Z

0

A good comparative study here

In place of isset you may have to use is_null.

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Mar 10, 2016 at 9:06

thatonepixel

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Comments

Exception · Accepted Answer · 2016-03-10 09:11:01Z

0

For your query I can suggest following will be solution if values are string

$array1 = array(0 => 'test1', 1 => 'test2', 2 => 'test3', 3 => '',4 => 'test4');
foreach ($array1 as $value) {
              if($value =="") {
                echo "EMPTY";
              } else {
                echo "Not empty";
             }
          }

There is good link that will help you to understand the difference

answered Mar 10, 2016 at 9:11

Exception

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Comments

Sanjay Chaudhari · Accepted Answer · 2016-03-10 09:26:33Z

-1

Please change your code with below code.

 foreach ($array1 as $value) {    
      if(!empty($value)) {
            echo "Not empty";
      } else {
            echo "EMPTY";
      }
 }

Note : isset() function not check the empty value. It's only check variable is set or not.

edited Mar 10, 2016 at 9:26

answered Mar 10, 2016 at 9:03

Sanjay Chaudhari

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2 Comments

deceze Over a year ago

isset && !empty is superfluous. Just use !empty. In fact, just use !$value, which will do just fine.

Sanjay Chaudhari Over a year ago

@deceze, Yes it's good but isset() not affected.

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