I made a huge mistake by mixing result with results and it took me around 4 hours to finally find the bug.
So here is the question, in PHP, is it possible that I can enforce PHP to report errors if I use an undefined/uninitialized variable.
thank you
Set error reporting to E_ALL and ensure that display_errors in php.ini is on.
php.ini
display_errors = On
PHP code
// If you cannot access the php.ini file
// you can do this within your PHP code instead
@ini_set('display_errors' '1');
error_reporting(E_ALL);
The default setting you have right now probably excludes notices, the kind of errors PHP raises on uninitialized variables, which could be something like this:
error_reporting(E_ALL & ~E_NOTICE);
error_reporting(E_ALL | E_STRICT) as E_ALL by itself does not include E_STRICT.yes, use error_reporting() and set it to E_ALL, like this:
error_reporting(E_ALL);
Set error reporting to report all errors. Either in php.ini or at runtime using error_reporting(E_ALL)
it already does report an error. something like this:
"Notice: Undefined variable: a in C:\wamp\www\testcenter\index.PHP on line 40"
maybe you didn't go specific enough. but you should try error_reporting(-1); as as if enforces the php to show some recomendations. a piece from the php manual about E_STRICT errors:
Enable to have PHP suggest changes to your code which will ensure the best interoperability and forward compatibility of your code.
just remember that error_reporting(-1); shows more errors than error_reporting(E_ALL); because E_STRICT errors are not included in the E_ALL constraint.
