New to bash script, i need to check if the first word in Group equals the second word in Users.
Group=`echo $rules | egrep -v 'Test'`
Users=`echo $rules | grep -i 'Test' | awk '{print substr($0, index($0,$2))}'`
if [ '$Group' -eq '$Users' ];
then
echo $Group
echo $Users
else
:
fi
Can I use something like this or how is this possible?
if [ '$Group $1' -eq '$Users $2' ];
or
if [ '^$Group' -eq '^$Users' ];
The operator -eq is used for integer comparison.
If you want to compare strings you must use = like this:
if [ "$a" = "$b" ]
which is equivalent to
if [ "$a" == "$b" ]
but NOT equivalent to (note the spaces)
if [ "$a"="$b" ]
However, if you want to use a regular expression (you used ^ which isn't a glob pattern wildcard) in a if statement look here
That said you should do the splitting before the if statement and put Users and Groups in two arrays.
if [ "$Group" -eq "$Users" ].