Exception Handling Python3

Question

I'm practicing exception handling and when I try to execute the following code, python doesn't handle the TypeError exception if i enter a text instead of number. Following is the code :

num1=input("Enter the first number : ")
num2=input("Enter the second number : ")
try:
    num1=int(num1)
    num2=int(num2)
except TypeError:
    print("Sorry, that wasn't a number, please try again")
else:
    print(add)

It raises a ValueError, not a TypeError

Farhan.K
– Farhan.K

2016-06-09 08:24:36 +00:00
Commented Jun 9, 2016 at 8:24 — Farhan.K
– Farhan.K, Commented Jun 9, 2016 at 8:24

user768518 · Accepted Answer · 2016-06-09 08:23:45Z

1

This is because you are not tracking the correct error:

>>> int("not a number")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: 'not a number'

ValueError is what you're looking for.

answered Jun 9, 2016 at 8:23

user768518

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3 Comments

Kushagra Chugh ੴ Over a year ago

Thank you, now it worked. Why do we use TypeError then?

user768518 Over a year ago

Quoting from docs.python.org/3/library/exceptions.html. TypeError - Raised when an operation or function is applied to an object of inappropriate type. The associated value is a string giving details about the type mismatch. Try typing '2' + 2 in python CLI.

Martijn Pieters Over a year ago

@KushagraChughੴ: input() always returns a string, and int() takes a string object as argument. If you were to pass something in that was not a string (and not any of the other accepted types) you'd get a TypeError, e.g. int(None). But since you always pass in a string, that's not the case here.

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