I have this array
Array
(
[result] => Array
(
[status] => nok
[reason] => Character not found.
)
[code] => 404
[content_type] => application/json;charset=utf-8
)
I want to check the [status], if it is "nok" it should appear "Match found".
My code:
$info = $r['result']['status'];
if (in_array("nok", $info))
{
echo "Match found";
}
else
{
echo "Match not found";
}
?>
the function in_array check if the value exists in an array, you don't give an array but a string.
You have two options:
change you code to this:
if (isset($r['result']) && in_array("nok", $r['result'])) { //add isset to not raise a warning when it doesn't exists
Or if the result is always the same you can do this:
if (isset($r['result']['status']) && $r['result']['status'] === 'nok') { //add isset to not raise a warning when it doesn't exists
In your case:
$r['result']['status']
is not an array but a string.
So you can ask for:
if(in_array("nok", $r['result']))
or
if($r['result']['status'] == "nok")
$info is not an array, it's a string. Try this instead:
if (in_array("nok", $r['result']))
{
echo "Match found";
}
else
{
echo "Match not found";
}
Or
if ($r['result']['status'] == "nok"){
You don't need to use in_array in this code. in_array searches a linear array for string values... so this is how you would use it:
$arr = array("dog", "cat", "mouse");
if(in_array("mouse", $arr)) echo "Eek, a mouse!";
You can just compare using normal logic since you are comparing a string to a string:
$info = $r['result']['status'];
if ($info == "nok")
{
echo "Match found";
}
else
{
echo "Match not found";
}
$r['result']['status']this is not an array . u can chk likeif($info == 'nok')if (in_array("nok", $info)){needs to beif ($info === "nok"){if (in_array("nok", $r['result'])){you can use this tooif (in_array("nok", $info)){needs to beif ($info === "nok"){orif (in_array("nok", $r['result'])){you can use this too