Insert a number to the random position in an array of random number

Question

I'm developing a simple game to add 2 number and select a result in a gridview. But I've only put a number to 1st or last position of my list's Array. How to add my result to the random position without give it an exactly index? Here is my code:

x=random.nextInt(11);
a=a+x;
for (int j=1;j<25;){
    int random=((int)(Math.random()*25))+1;
    if (!list.contains(random)){
        list.add (a+random);
        j++;
    }
}

Nicolas Filotto · Accepted Answer · 2016-06-23 09:53:34Z

1

Simply adds your random numbers in your list as you do then call Collections.shuffle(List) to reorder your List randomly.

answered Jun 23, 2016 at 9:53

Nicolas Filotto

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Adarsh · Accepted Answer · 2016-06-23 09:47:27Z

0

First create array with N Values (Blank/Null we can say)
Now you need to generate random number between 0 to N-1
Use above value as index and store you value.

answered Jun 23, 2016 at 9:47

Adarsh

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Comments

Laurence Pardz · Accepted Answer · 2016-06-23 10:09:03Z

0

private List <Integer> createRandomIndexes() {
    List<Integer> indexes = new ArrayList<>();
    for (int i = 1; i < 25; i++) {
        indexes.add(i);
    }
    Collections.shuffle(indexes);
    return indexes;
}

Here's the key to random

Collections.shuffle(indexes);

answered Jun 23, 2016 at 10:09

Laurence Pardz

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