how to decode a non unicode character in python?

Question

I have a string say s = 'Chocolate Moelleux-M\xe8re' When i am doing:

In [14]: unicode(s)
---------------------------------------------------------------------------
UnicodeDecodeError                        Traceback (most recent call last)
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe8 in position 20: ordinal not in range(128)

Similarly when i am trying to decode this by using s.decode() it returns same error.

In [13]: s.decode()
---------------------------------------------------------------------------
UnicodeDecodeError                        Traceback (most recent call last)
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe8 in position 20: ordinal not in range(128)

How to decode such string into unicode.

Community · Accepted Answer · 2017-05-23 12:28:29Z

I have had to face this problem one too many times. The problem that I had contained strings in different encoding schemes. So I wrote a method to decode a string heuristically based on certain features of different encodings.

def decode_heuristically(string, enc = None, denc = sys.getdefaultencoding()):
    """
    Try to interpret 'string' using several possible encodings.
    @input : string, encode type.
    @output: a list [decoded_string, flag_decoded, encoding]
    """
    if isinstance(string, unicode): return string, 0, "utf-8"
    try:
        new_string = unicode(string, "ascii")
        return string, 0, "ascii"
    except UnicodeError:
        encodings = ["utf-8","iso-8859-1","cp1252","iso-8859-15"]

        if denc != "ascii": encodings.insert(0, denc)

        if enc: encodings.insert(0, enc)

        for enc in encodings:
            if (enc in ("iso-8859-15", "iso-8859-1") and
                re.search(r"[\x80-\x9f]", string) is not None):
                continue

            if (enc in ("iso-8859-1", "cp1252") and
                re.search(r"[\xa4\xa6\xa8\xb4\xb8\xbc-\xbe]", string)\
                is not None):
                continue

            try:
                new_string = unicode(string, enc)
            except UnicodeError:
                pass
            else:
                if new_string.encode(enc) == string:
                    return new_string, 0, enc

        # If unable to decode,doing force decoding i.e.neglecting those chars.
        output = [(unicode(string, enc, "ignore"), enc) for enc in encodings]
        output = [(len(new_string[0]), new_string) for new_string in output]
        output.sort()
        new_string, enc = output[-1][1]
        return new_string, 1, enc

To add to this this link gives a good feedback on why encoding etc - Why we need sys.setdefaultencoging in py script

Habbie · Accepted Answer · 2010-10-06 06:57:41Z

4

You need to tell s.decode your encoding. In your case s.decode('latin-1') seems fitting.

answered Oct 6, 2010 at 6:57

Habbie

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5 Comments

user12345 Over a year ago

is it going to help me in all situation? Is there any generalised solution?

user12345 Over a year ago

Can we remove those character such as '\x' in my example , from the original string.

johnbaum Over a year ago

@alis: You could use chardet (chardet.feedparser.org) to guess the encoding.

Habbie Over a year ago

s.decode('ascii','ignore') will take out all 'weird' characters

Bernd Petersohn Over a year ago

@alis: This converts Chocolate Moelleux-Mère into Chocolate Moelleux-Mre. I don't understand how this could be an actual solution for anything. Further, assume you encounter an ISO-8859-5 encoded version of Мойст Шоколад Матери. If you decode that by ignoring all non-ascii characters, all that will remain are two blanks. In other words, decode your strings by specifying the matching encoding. In your example, unicode(s, 'latin-1').

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