Sourcing bash script, how don't display the output?

Question

I have two scripts, the 'main' script, script A and a script B which contains some variables. In script A, I include script B for use the variable defined in the script B like so:

scriptA:

. ./scriptb
...
echo $toto

scriptB:

export toto="hello !"

When I run my script A, I get the output:

$./scriptA
/home/user/scriptb
hello !

My question is how to remove the undesired /home/user/scriptb from output.

With the data you provide in your question is not possible to know what's going on. — Vicente Olivert Riera
– Vicente Olivert Riera, Commented Aug 30, 2016 at 23:19
Where is that output coming from? You haven't shown the relevant code so we can't say. You need to find the command printing that output and modify/silence it. — Etan Reisner
– Etan Reisner, Commented Aug 31, 2016 at 1:31

Vicente Olivert Riera · Accepted Answer · 2016-08-30 23:25:57Z

1

The code you provided in your question doesn't have any problem:

$ cat scripta
. ./scriptb
echo $toto

$ cat scriptb 
export toto="hello!"

$ ./scripta 
hello!

answered Aug 30, 2016 at 23:25

Vicente Olivert Riera

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