Regex for parsing sub string of URL

Question

I have the following string:

function init() {

            $.get("/example/abc/include.txt", function(script) {
               code goes here
            });
            $.get("<http>://abc.com/example/abc/dontinclude.txt", function (script) {
                code goes here
                }
            });
        }

I am trying to parse the above string to list all the URL's which starts from /example and ends with file name like abc.txt.

So the desired list should be: /example/abc/include.txt

I tried with the following regex :

(\/)[^\s\/]?(example\/)(\w+\/)*(\w+.\w{3,4})

But it list two URLs as below:

/example/abc/include.txt
/example/abc/dontinclude.txt

I changed the above regex to :

\"(\/)[^\s\/]?(example\/)(\w+\/)*(\w+.\w{3,4})\"

This returns the required URL but I want exclude the double quotes from the result.

Any Idea how to remove the double quotes using the regex?

Thanks.

Yosh · Accepted Answer · 2016-09-02 11:46:57Z

1

It depends on how you read the matched results. You could use another group surrounding everything but the double quotes:

\"((\/)[^\s\/]?(example\/)(\w+\/)*(\w+\.\w{3,4}))\"

or you could use a positive lookbehind, that ensures that the character before is a double quote:

(?<=\")(\/)[^\s\/]?(example\/)(\w+\/)*(\w+\.\w{3,4})

answered Sep 2, 2016 at 11:46

Yosh

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3 Comments

Pabdev Over a year ago

Thanks for the reply. The positive look-forward (?<=\") is not c# regex flavor. I tried the same in c# flavor (?=\")(\/)[^\s\/]?(example\/)(\w+\/)*(\w+\.\w{3,4}). But it didn't work.

Yosh Over a year ago

The positive lookbehind is C# regex flavor. (see: msdn.microsoft.com/de-de/library/az24scfc(v=vs.110).aspx). Have you escaped the double quote correct? @"(?<=\"")(\/)[^\s\/]?(example\/)(\w+\/)*(\w+\.\w{3,4})"

Pabdev Over a year ago

Yes @Yosh you are right. I tested it in wrong tool. Its working fine now. Thanks.

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