0

I am trying to find a way to get results where the Occupancy in the latest Inspection_date and the one before the last are not equal.

In this example only number RoomID 2 will be the only result because: the Occupancy for OrderID 201 = 'Vacant' <> to the Occupancy for OrderID 202 = 'Occupied'.

I have the beginning of the query but cannot seem to find a good logic to end the query.

| RoomID | OrderID | Occupancy | rn |
+--------+---------+-----------+----+
| 01     | 101     | Vacant    | 1  |
| 01     | 102     | Vacant    | 2  |
| 01     | 103     | Occupied  | 3  |
| 01     | 104     | Vacant    | 4  |
| 02     | 201     | Vacant    | 1  |
| 02     | 202     | Occupied  | 2  |
| 02     | 203     | Vacant    | 3  |
| 03     | 301     | Occupied  | 1  |
| 03     | 302     | Occupied  | 2  |
| 03     | 303     | Occupied  | 3  |
| 03     | 304     | Occupied  | 4  |
| 04     | 401     | Occupied  | 1  |
| 04     | 402     | Occupied  | 2  |
| 04     | 403     | Vacant    | 3  |
| 04     | 404     | Occupied  | 4  |


SELECT i.room_number, order_number, Occupancy , row_number() OVER(PARTITION BY room_number ORDER BY Inspection_date DESC) rn 
FROM #inspection_data i 

1 Answer 1

1

In SQL Server 2012+, you can use lag(), so something like this:

SELECT i.*
FROM (SELECT i.room_number, order_number, Occupancy ,
             ROW_NUMER() OVER (PARTITION BY room_number ORDER BY Inspection_date DESC) as seqnum,
             LAG(Occupancy) OVER (PARTITION BY room_number ORDER BY Inspection_date) as prev_Occupancy
      FROM #inspection_data i
     ) i
WHERE prev_Occupancy <> Occupancy AND seqnum = 1 ;
Sign up to request clarification or add additional context in comments.

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.